Design Considerations for Evaporator Drums and Calandria
Evaporator drums are critical components in chemical evaporation systems, and their design requires careful consideration of various factors. Most evaporator drums operate under vacuum conditions, with a typical external pressure rating of 0.1 N/m2.
Evaporator Drum Design
The evaporator drum consists of several key components:
- Conical Bottom Portion: Designed for a similar pressure rating as the drum, this section provides a smooth transition for the vapor flow.
- Top Head Section: This section, which is preferred to be flanged or flared, dished, or conical in shape, facilitates easy access for maintenance and inspection.
- Cylindrical Pieces: The vapor drum is constructed from separate cylindrical pieces joined by flanges, allowing for easy assembly and disassembly.
- Large Nozzles: Manholes, sight glasses, and other large nozzles are reinforced with compensating rings to ensure structural integrity.
- Supports: Brackets welded to the vapor drum or calandria provide additional support and stability.
Calandria Design
The calandria, a tubular heating surface, is designed based on the shell and tube heat exchanger model. Since steam under pressure is typically used as the heating medium, the design takes into account the pressure rating of the system. The calandria and vapor drum are connected by flanged joints or directly welded.
Design Factors and Heat Balance
The design factors, heating surface area, and steam requirement are derived from the overall and individual heat balance of the multiple-effect chemical evaporation system. This involves careful consideration of the heat transfer coefficients, temperature differences, and mass flow rates of the various streams involved.
By carefully considering these design factors and incorporating them into the design of the evaporator drum and calandria, engineers can create efficient and effective chemical evaporation systems that meet the required process conditions.
- CF = Specific heat of feed (KJ/KgoC)
- TF =Temperature of feed,oC
- WF = Feed, Kg/hr
- Ts = Saturation temperature of steam to first effect, oF
- Ws = Steam to first effect, Kg/hr
- W1-4 = Total water removed by evaporation
- m = mass flowrate
- p = product
- v = vapor
- f = feed
- U = heat transfer coefficient
Design of five effect evaporators system:
The overall balance of the evaporator would be: m·f = m·p4 +m·vOverall vapor balance: m·v = m·v1 + m·v2 + m·v3 + m·v4
Solute balance | Energy balance equations | |
First effect | mf = mp1 + mv1 mfxf = mpxp1 |
ms .λs = mf Cpf (T1-Tf) + mv1 .λv1 |
Second effect | mp1 = mp2 + mv2 mp1xp1 = mp2xp2 |
mv1 .λv1= mp1Cpf (T2-T1) + mv2 .λv2 |
Third effect | mp2 = mp3 + mv3 mp2xp2 = mp3xp3 |
mv2 .λv2 = mp2Cpf (T3-T2) + mv3 .λv3 |
Fourth effect | mp3 = mp4 + mv4 mp3xp3 = mp4xp4 |
mv3 .λv3= mp3Cpf (T4-T3) + mv4 .λv4 |
Fifth effect | mp4 = mp5 + mv5 mp4xp4 = mp5xp5 |
mv4 .λv4= mp4Cpf (T5-T4) + mv5 .λv5 |
Assuming the steam temperature is 120oC
The energy value of steam = 2201.6 KJ/kg from steam tables
Basis: For the mass flow rate of the entering juice ‘m’= 208.33tonnes/hr.
Pressure maintained | Temperature from steam tables | Latent heat of vaporization | |
First effect | 1.60687atm= 755 mm Hg | 99.819oC | 2257.4 KJ/kg |
Second effect | 1.19989atm = 480.6 mm Hg | 87.616oC | 2289.4 KJ/kg |
Third effect | 0.81229atm = 302.8mm Hg | 75.844oC | 2319.2 KJ/kg |
Fourth effect | 0.44407atm = 99.6mm Hg | 60oC | 2379.1 KJ/kg |
Fifth effect | 0.09527atm | 50oC |
Assuming the value of xf =0.15
By substituting the values in the balance equations and solving the simultaneous equations we get the following values:
Type | Vapor flow rates(tonnes/hr) | Product flow rate(tonnes/hr) | Mass fractions in terms of xp |
1st effect | 66 | 142.33 | 0.1804 |
2nd effect | 64 | 79.33 | 0.2313 |
3rd effect | 17 | 62.33 | 0.32 |
4th effect | 10 | 52.33 | 0.6 |
5th effect | 1 | 51.33 | 0.6 |
Assuming the mass flow rate of steam, ms = 66tonnes/hr
Steam balance:
- Steam consumption ms is = 66tonnes/hr
- Capacity mv = 41532.3499 Kg/hr
- Steam economy = 4.619
Where Q=ms λs
- ms λs = Q1 = U1A1ΔT1
- ms λs = Q2 =U2A2 ΔT2
- ms λs = Q3 =U3A3 ΔT3
- ms λs = Q4 =U4A4 ΔT4
ms λs=UA ΔT | U, KJ/(m2.hr. oC) | |
First effect | 66000×2187.18 = U1×2700×(125-110) | 3564. 3 |
Second effect | 63000×2201.6 = U2×2500×(110-102) | 7012 |
Third effect | 17000×227.168 = U3×1200×(102-90) | 2530.6 |
Fourth effect | 9310×2281.6 = U4×800×(90-80) | 2658.861 |
Fifth effect | 9320×2353 = U5×300×(80-60) | 3663.41 |
Calculation for number of tubes:
Formula for number of tubes= n × π × D × L = AType | Vapor flow rates(kg/hr) | Product flow rate(kg/hr) | U(KJ/m2.hr oC) | Area, A=m2 | n, no.of Tubes |
1st effect | 66000 | 142.33 | 3564.3 | 2700 | 4775 |
2nd effect | 63000 | 79.33 | 7012 | 2500 | 4421 |
3rd effect | 17000 | 62.33 | 2530.7 | 1200 | 2122 |
4th effect | 9320 | 52.33 | 2658.86 | 800 | 1415 |
5th effect | 1000 | 51.33 | 3663.41 | 300 | 531 |
Model mechanical design of sugar industry evaporators:
- Temperature in evaporator = 99.819 oC
- Diameter of tubes: 42 ID × 45 OD
- No. of tubes: 4775
- Length of the tube = 4m
Calandria:
- Pressure = 755 mm
- Heating surface area = 2700 m2
- Material of construction: Stainless Steel
- Permissible stress for low carbon steel—98 N/mm2
- Modulus of elasticity for low carbon steel = 19.0 X 104 N/mm2
- Modulus of elasticity for SS 304= 9.5 X 104N/mm2
- No. of tubes Nt = 4775
- Pitch of the tube = Pt/Do = 67.5mm
- Area occupied by tubes As = n X 0.866 X ST2 / β = 18.4 m2
- Required area for central down take = 40% X Cross-sectional area of the tube = 0.4 X 2110 X π X0.0452 / 4 = 3.04m2
- The actual area of downtake is 3.1m2
- The total area of the tube sheet is = 24.03m2
- The diameter of the tube sheet is = 5.96m
- Calandria sheet thickness: ts = pD / 2fJ – p = 5.48mm
Tube sheet thickness:
F = √(K/[2+3K])
Where K = Ests(D0-ts) / EtN Ti(d0-tt)
- Es = modulus of elasticity of shell material
- ts = Sheet thickness
- tt = Tube thickness
- k = 0.15527
- F = 0.250936
- t = FG√(0.25p)/f = 5.48mm
Bottom flange of calandria:
- The thickness of the flange = 40mm
- Number of bolts = 112
- Outside diameter = 3894mm
- Pitch circle diameter = 3825mm
- Size of bolts = 20M
Evaporator drum:
- Rd = V/A 0.0172 X (ρL – ρV / ρV)1/2
- Let Rd = 0.8
- Here V = volumetric flow rate of vapor in m3/sec = 66
- A = 31.32m2
- The diameter of drum is 8m